Ola day
Teorema de Tales
(x - 1)/(x - 1 + 3) = (x + 4)/(x + 4 + x)
(x - 1)/(x + 2) = (x + 4)/(2x + 4)
(2x + 4)*(x - 1) = (x + 4)*(x + 2)
2x² + 2x - 4 = x² + 6x + 8
x² - 4x - 12 = 0
delta
d² = 16 + 48 = 64
d = 8
x = (4 + 8)/2 = 6
lados
AB = x + 2 = 8
AC = 2x + 4 = 16
BC = 14
P = 8 + 16 + 14 = 38 cm
pronto
Olá Day,
(x-1)/3=(x+4)/x
(x-1).x=3.(x+4)
x²-x=3x+12
x²-x-3x-12=0
x²-4x-12=0
(x-6).(x+2)=0
x-6=0 => x=6 cm
AD=x-1 --->AD=6-1 => AD=5 cm
AE=x+4---> AE=6+4 => AE=10 cm
EC=x --> EC=6 cm
AB=AD+DB => AB=5+3 => AB=8 cm
AC=AE+EC => AC=10+6 => AC=16 cm
BC=14 cm
2p=AB+AC+BC
2p=8+16+14
2p=24+14
2p=38 cm #
Copyright © 2024 QUIZLIB.COM - All rights reserved.
Answers & Comments
Verified answer
Ola day
Teorema de Tales
(x - 1)/(x - 1 + 3) = (x + 4)/(x + 4 + x)
(x - 1)/(x + 2) = (x + 4)/(2x + 4)
(2x + 4)*(x - 1) = (x + 4)*(x + 2)
2x² + 2x - 4 = x² + 6x + 8
x² - 4x - 12 = 0
delta
d² = 16 + 48 = 64
d = 8
x = (4 + 8)/2 = 6
lados
AB = x + 2 = 8
AC = 2x + 4 = 16
BC = 14
P = 8 + 16 + 14 = 38 cm
pronto
Olá Day,
(x-1)/3=(x+4)/x
(x-1).x=3.(x+4)
x²-x=3x+12
x²-x-3x-12=0
x²-4x-12=0
(x-6).(x+2)=0
x-6=0 => x=6 cm
AD=x-1 --->AD=6-1 => AD=5 cm
AE=x+4---> AE=6+4 => AE=10 cm
EC=x --> EC=6 cm
AB=AD+DB => AB=5+3 => AB=8 cm
AC=AE+EC => AC=10+6 => AC=16 cm
BC=14 cm
2p=AB+AC+BC
2p=8+16+14
2p=24+14
2p=38 cm #