y=ln(x)/x²
y'=[ln(x)'.x²-ln(x).x² ']/(x²)²
y'=[1/x.x²-ln(x).2x]/(x^4)
y'=[x-2xln(x)]/(x^4)
y'=x[1-2ln(x)]/(x^4)
y'=[1-2ln(x)]/(x^3)
lnx/x^2
lnx'*x^2-x^2'*lnx/(x^2)^2
(1/x)*x^2-2x*lnx/x^4
x-2x*lnx/x^4
x(1-2lnx)/x^4
1-2lnx/x^3
Respondam o meu tb pf sao só 2 perguntinhas preciso mt de ajuda!!!!!!!!
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y=ln(x)/x²
y'=[ln(x)'.x²-ln(x).x² ']/(x²)²
y'=[1/x.x²-ln(x).2x]/(x^4)
y'=[x-2xln(x)]/(x^4)
y'=x[1-2ln(x)]/(x^4)
y'=[1-2ln(x)]/(x^3)
lnx/x^2
lnx'*x^2-x^2'*lnx/(x^2)^2
(1/x)*x^2-2x*lnx/x^4
x-2x*lnx/x^4
x(1-2lnx)/x^4
1-2lnx/x^3
Respondam o meu tb pf sao só 2 perguntinhas preciso mt de ajuda!!!!!!!!
http://br.answers.yahoo.com/question/index;_ylt=Aq...