suplemento = 180-x
complemento = 90-x
(180-x) = 3.(90-x) + 50
180-x = 270-3x + 50
2x = 140
x = 70º
.........
(180-x) + 50 = 3(90-x)
180 - x + 50 = 270 - 3x
2x = 40
x = 40/2
x = 20
medida do angulo 20º
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Verified answer
suplemento = 180-x
complemento = 90-x
(180-x) = 3.(90-x) + 50
180-x = 270-3x + 50
2x = 140
x = 70º
.........
(180-x) + 50 = 3(90-x)
180 - x + 50 = 270 - 3x
2x = 40
x = 40/2
x = 20
medida do angulo 20º