Como se resolve equações matriciais?
X + (4..3) (5...0)
(1..1) = (2..3)
(2..0) (7..8)
Ajude se conseguir;
Desde já eu agradeço
(1/2....1) (3/2....4)
(0......2) + (3.......7) = X - (-1...-3)
(-2....4)
More Questions From This User See All
X + (4..3) (5...0)
(1..1) = (2..3)
(2..0) (7..8)
Ajude se conseguir;
Desde já eu agradeço
(1/2....1) (3/2....4)
(0......2) + (3.......7) = X - (-1...-3)
(-2....4)
Copyright © 2024 QUIZLIB.COM - All rights reserved.
Answers & Comments
Verified answer
a)
se for
........ (4..3)........ (5...0)
X..+..(1..1) ...=....(2..3)
.........(2..0)........ (7..8)
(a..b)..... (4..3)........ (5...0)
(c..d)..+..(1..1) ...=...(2...3)
(e..f).......(2..0)........ (7....8)
a+4=5 ==>a=1
b+3=0 ==>b=-3
c+1=2 ==>c=1
d+1=3 ==>d=2
e+2=7 ==>e=5
f+0=8 ==>f=8
_________________________
b)
Se for:
(1/2....1) .....(3/2....4)............. (-1...-3)
(............) .+..(...........)...= X -.. (..........)
(0......2.) . ...(3.......7) ..............(-2....4)
(1/2....1) .....(3/2....4).....(a...b)........ (-1...-3)
(............) .+..(...........)...=( .......)...-... (..........)
(0......2.) . ...(3.......7) .....(c...d).........(-2....4)
1/2+3/2=a-(-1) ==>a=1
1+4=b-(-3) ==>b=2
0+3=c-(-2) ==>c=1
2+7=c-4 ==>13