a) log2 (x – 1 ) < log2 3
b) log4 ( 3x – 2 ) > log4 ( 5x – 1 )
c) log (x + 13 ) > log 2
Desculpa não ter citado, a base é o numero que vem logo após o log
<=> x - 1 < 3
<=> x < 3 + 1
<=> x < 4
<=> 3x - 2 > 5x - 1
<=> 3x - 5x > 2 - 1
<=> -2x > 1
<=> x < -1/2
<=> x + 13 > 2
<=> x > -13 + 2
<=> x > -11
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a) log2 (x – 1 ) < log2 3
<=> x - 1 < 3
<=> x < 3 + 1
<=> x < 4
b) log4 ( 3x – 2 ) > log4 ( 5x – 1 )
<=> 3x - 2 > 5x - 1
<=> 3x - 5x > 2 - 1
<=> -2x > 1
<=> x < -1/2
c) log (x + 13 ) > log 2
<=> x + 13 > 2
<=> x > -13 + 2
<=> x > -11