Given that y is positive, make y the subject of y = √ay² + n Show clear algebraic working.?
I'm trying to revise for my I-GCSE maths test in a few months so I decided to go over my mocks and past papers and revise every subject and question I've lost marks on previously. But no matter what I do the answer to this question alludes me. Whether its websites not providing the correct kinds of explanation or my own inability to do such a question I don't know but as soon as I square both sides to remove the square root and am faced with a y² on both sides of the equation and become stuck and befuddled.
Any help that can be offered is greatly appreciated and I offer many thanks and gratitude in advance to any kind soul prepared to help me.
( If it isn't clear the square route applies to the entire right hand side of the equation.)
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when you get y^2 = ay^2 + n, carry the ay^2 to the left hand side:
y^2 - ay^2 = n
y^2(1-a) = n
y^2 = n/(1-a)
Therefore:
y= +/-sqrt(n/(1-a))
that should be the answer.
y = â(ay² + n)
y² = ay² + n
y²(1 - a) = n
y² = n/(1 - a)
y = 屉[n/(1 - a)]