In words....d = the square root of 3h over 2.
Do you mean d = √(3h/2)?
Square both sides:
d² = √(3h/2)²
d² = 3h/2
Then, multiply both sides by 2/3 to obtain:
h = 2d²/3
I hope this helps!
If only 3h is square rooted then square both sides to get
d^2 = 3h / 4
Now multiply both sides by 4/3 to get
(4d^2) / 3 = h
If 3h and 2 are under the radical sign, still square both sides. This gives d^2 = 3h / 2 now multiply both sides by 2/3 to get
(2 d^2) / 3 = h
Just be sure to specify for sure which terms are under the radical sign.
The square root of 3h over 2 mean ^--(3h) / 2 only the 3h has the radical.
The square root of the quantity 3h over 2 each term is under the radical sign.
Doesn't seem like much, but it is.
Is it D = [√(3h/2)]?
if yes, then square both sides.
D^2 = (3h/2)
multiply both sides by 2.
2D^2 = 3h
then divide the left hand side by 3.
(2D^2)/3 = h
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Answers & Comments
Verified answer
Do you mean d = √(3h/2)?
Square both sides:
d² = √(3h/2)²
d² = 3h/2
Then, multiply both sides by 2/3 to obtain:
h = 2d²/3
I hope this helps!
If only 3h is square rooted then square both sides to get
d^2 = 3h / 4
Now multiply both sides by 4/3 to get
(4d^2) / 3 = h
If 3h and 2 are under the radical sign, still square both sides. This gives d^2 = 3h / 2 now multiply both sides by 2/3 to get
(2 d^2) / 3 = h
Just be sure to specify for sure which terms are under the radical sign.
The square root of 3h over 2 mean ^--(3h) / 2 only the 3h has the radical.
The square root of the quantity 3h over 2 each term is under the radical sign.
Doesn't seem like much, but it is.
Is it D = [√(3h/2)]?
if yes, then square both sides.
D^2 = (3h/2)
multiply both sides by 2.
2D^2 = 3h
then divide the left hand side by 3.
(2D^2)/3 = h