A potter’s wheel of radius 47.54 cm and mass 108.4 kg is freely rotating at 49.2 rev/min. The potter can stop?
A potter’s wheel of radius 47.54 cm and mass 108.4 kg is freely rotating at 49.2 rev/min. The potter can stop the wheel in 6.469 s by pressing a wet rag against the rim and exerting a radially inward force of 66.7 N.
What is the angular acceleration of the wheel?
part 2
How much torque does the potter apply to the wheel?
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Hello
the frequency of the wheel is 49,2/60 = 0,82 Hz
ω = 2pif = 5,1522 rad/s (= angular frequency)
α = 5,1522/6,469 = 0,79644 rad/s^2 (angular acceleration = rather - 0,7944 rad/s^2 when it is called acceleration).
τ = I*α = (1/2 mR^2)*α
= (0.5*108,4 kg *0,4754^2 m^2 )*0,79644 rad/s^2 = 9,7559 Nm
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